There appeared a task to encode a binary data to base64 and then decode it back. There’re many solutions, but this one I liked very much.
#include "boost/archive/iterators/base64_from_binary.hpp"
#include "boost/archive/iterators/binary_from_base64.hpp"
#include "boost/archive/iterators/transform_width.hpp"
#include <string>
#include <iostream>
using namespace std;
using namespace boost::archive::iterators;
typedef
base64_from_binary<
transform_width<string::const_iterator, 6, 8>
> base64_t;
typedef
transform_width<
binary_from_base64<string::const_iterator>, 8, 6
> binary_t;
int main()
{
string str("Hello, world!");
cout << str << endl;
string enc(base64_t(str.begin()), base64_t(str.end()));
cout << enc << endl;
string dec(binary_t(enc.begin()), binary_t(enc.end()));
cout << dec << endl;
return 0;
}It’s simple enough, isn’t it? But the world is not ideal, and because of a bug decoding doesn’t work, as expected. Fortunately, the bug can be worked around with a little hack.
2 коментарі:
I want to use this very badly, but doesn't work. It crashes on "string enc(base64_t(str.begin()), base64_t(str.end()));" this line only. It works when I use str.end()-1 instead of str.end(). I posted why on boost mailing list and got a reply that it works only for data with 3 buty boundry. Do you have any idea what theose 6 and 8 represent? I couldn't find any decent documentation.
Don’t use this code, this piece is just internals of boost::serialization. Try to use an open source library for base64 transformation instead (there’re plenty of them around).
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