There appeared a task to encode a binary data to base64 and then decode it back. There’re many solutions, but this one I liked very much.
#include "boost/archive/iterators/base64_from_binary.hpp" #include "boost/archive/iterators/binary_from_base64.hpp" #include "boost/archive/iterators/transform_width.hpp" #include <string> #include <iostream> using namespace std; using namespace boost::archive::iterators; typedef base64_from_binary< transform_width<string::const_iterator, 6, 8> > base64_t; typedef transform_width< binary_from_base64<string::const_iterator>, 8, 6 > binary_t; int main() { string str("Hello, world!"); cout << str << endl; string enc(base64_t(str.begin()), base64_t(str.end())); cout << enc << endl; string dec(binary_t(enc.begin()), binary_t(enc.end())); cout << dec << endl; return 0; }
It’s simple enough, isn’t it? But the world is not ideal, and because of a bug decoding doesn’t work, as expected. Fortunately, the bug can be worked around with a little hack.
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I want to use this very badly, but doesn't work. It crashes on "string enc(base64_t(str.begin()), base64_t(str.end()));" this line only. It works when I use str.end()-1 instead of str.end(). I posted why on boost mailing list and got a reply that it works only for data with 3 buty boundry. Do you have any idea what theose 6 and 8 represent? I couldn't find any decent documentation.
Don’t use this code, this piece is just internals of boost::serialization. Try to use an open source library for base64 transformation instead (there’re plenty of them around).
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